What are the solutions to the equation 6=x^2-x ?

The solutions to the equation 6=x^2-x are x=3,x=-2

Find the zeros of 6=x^2-x

The zeros of 6=x^2-x are x=3,x=-2

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6 = x^{2} - x

x = 3, x = - 2

Solution steps

6 = x^{2} - x

Switch sides

x^{2} - x = 6

Move

6

to the left side

x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

x = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

\frac{x}{6} + \frac{1}{3} = \frac{1}{12}

5^{- x}

x^{2} + x + \frac{1}{4}

\frac{5 a}{5 a + 5} \cdot \frac{10 a + 10}{a}

100 x^{2} + 20 x + 1

What are the solutions to the equation 6=x^2-x ?
The solutions to the equation 6=x^2-x are x=3,x=-2
Find the zeros of 6=x^2-x
The zeros of 6=x^2-x are x=3,x=-2