What is (9-2i)/(i-5) ?

The solution to (9-2i)/(i-5) is -47/26+1/26 i

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simplify (9-2i)/(i-5)

simplify

\frac{9 - 2 i}{i - 5}

- \frac{47}{26} + \frac{1}{26} i

Solution steps

\frac{9 - 2 i}{i - 5}

Rewrite

i - 5

in standard complex form:

- 5 + i

= \frac{9 - 2 i}{- 5 + i}

Multiply by the conjugate

\frac{- 5 - i}{- 5 - i}

= \frac{( 9 - 2 i ) ( - 5 - i )}{( - 5 + i ) ( - 5 - i )}

Simplify

\frac{( 9 - 2 i ) ( - 5 - i )}{( - 5 + i ) ( - 5 - i )} : \frac{- 47 + i}{26}

= \frac{- 47 + i}{26}

Rewrite in standard complex form:

- \frac{47}{26} + \frac{1}{26} i

= - \frac{47}{26} + \frac{1}{26} i

(x - 1) (x - 2) (x + 3) (x + 4)

\frac{\frac{n + 3}{2 n - 6}}{\frac{n + 3}{3 n - 9}}

(x + 1)^{2} - 9

a - (b + a) + (- a + b) - (- a + 2 b)

(6 i - 2) + (3 - 4 i)