What is 2/(z+3)+1/(z-1) ?

The solution to 2/(z+3)+1/(z-1) is (3z+1)/((z+3)(z-1))

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simplify 2/(z+3)+1/(z-1)

simplify

\frac{2}{z + 3} + \frac{1}{z - 1}

\frac{3 z + 1}{( z + 3 ) ( z - 1 )}

Solution steps

\frac{2}{z + 3} + \frac{1}{z - 1}

Least Common Multiplier of

z + 3, z - 1 : (z + 3) (z - 1)

Adjust Fractions based on the LCM

= \frac{2 ( z - 1 )}{( z + 3 ) ( z - 1 )} + \frac{z + 3}{( z + 3 ) ( z - 1 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{2 ( z - 1 ) + z + 3}{( z + 3 ) ( z - 1 )}

Simplify

2 (z - 1) + z + 3 : 3 z + 1

= \frac{3 z + 1}{( z + 3 ) ( z - 1 )}

9 (\frac{35}{6})^{2} + 3 (\frac{1}{6})

2 sin^{2} (x) - 1

\frac{( 10 i )}{( 1 - 2 i )}

\frac{1}{2} (9.8)

x^{4} - 6 x^{3} - 11 x^{2} + 96 x - 80

What is 2/(z+3)+1/(z-1) ?
The solution to 2/(z+3)+1/(z-1) is (3z+1)/((z+3)(z-1))