What are the solutions to the equation 0=6x^2-23x+20 ?

The solutions to the equation 0=6x^2-23x+20 are x= 5/2 ,x= 4/3

Find the zeros of 0=6x^2-23x+20

The zeros of 0=6x^2-23x+20 are x= 5/2 ,x= 4/3

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0 = 6 x^{2} - 23 x + 20

x = \frac{5}{2}, x = \frac{4}{3}

Decimal Notation

x = 2.5, x = 1.33333 \dots

Solution steps

0 = 6 x^{2} - 23 x + 20

Switch sides

6 x^{2} - 23 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 6 \cdot 20}{2 \cdot 6}

(- 23)^{2} - 4 \cdot 6 \cdot 20 = 7

x_{1, 2} = \frac{- ( - 23 ) \pm 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 7}{2 \cdot 6}, x_{2} = \frac{- ( - 23 ) - 7}{2 \cdot 6}

x = \frac{- ( - 23 ) + 7}{2 \cdot 6} : \frac{5}{2}

x = \frac{- ( - 23 ) - 7}{2 \cdot 6} : \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{4}{3}

2. 2^{2}

- 3 r^{2} + 27 = 0

- x^{2} - 4 x + 4 = 0

5 (2 y) - y = 72

\frac{2 x - 1}{3} = 5

What are the solutions to the equation 0=6x^2-23x+20 ?
The solutions to the equation 0=6x^2-23x+20 are x= 5/2 ,x= 4/3
Find the zeros of 0=6x^2-23x+20
The zeros of 0=6x^2-23x+20 are x= 5/2 ,x= 4/3