What is factor x^4-y^2+2x^2+1 ?

The solution to factor x^4-y^2+2x^2+1 is (x^2+1+y)(x^2+1-y)

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factor x^4-y^2+2x^2+1

factor

x^{4} - y^{2} + 2 x^{2} + 1

(x^{2} + 1 + y) (x^{2} + 1 - y)

Solution steps

x^{4} - y^{2} + 2 x^{2} + 1

Factor

x^{4} + 2 x^{2} + 1 : (x^{2} + 1)^{2}

= (x^{2} + 1)^{2} - y^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x^{2} + 1)^{2} - y^{2} = ((x^{2} + 1) + y) ((x^{2} + 1) - y)

= ((x^{2} + 1) + y) ((x^{2} + 1) - y)

Apply rule:

(a) = a

(x^{2} + 1) = x^{2} + 1

= (x^{2} + 1 + y) (x^{2} + 1 - y)

\frac{( 3 x ^{4} - 6 x ^{3} + 19 x - 10 - 7 x ^{2} )}{( x - 2 )}

(3 b + 2 a)^{2}

(\frac{9 m ^{4} n ^{10}}{- 3 m ^{2} n ^{5}})^{- 1}

\frac{2 ^{12}}{2 ^{8}}

\frac{n ^{4} + 2 n ^{2} - 48}{n ^{2} + 8}

What is factor x^4-y^2+2x^2+1 ?
The solution to factor x^4-y^2+2x^2+1 is (x^2+1+y)(x^2+1-y)