What is (x^2-xy+4x-4y)/(x^2-2xy+y^2) ?

The solution to (x^2-xy+4x-4y)/(x^2-2xy+y^2) is (x+4)/(x-y)

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simplify (x^2-xy+4x-4y)/(x^2-2xy+y^2)

simplify

\frac{x ^{2} - x y + 4 x - 4 y}{x ^{2} - 2 x y + y ^{2}}

\frac{x + 4}{x - y}

Solution steps

\frac{x ^{2} - x y + 4 x - 4 y}{x ^{2} - 2 x y + y ^{2}}

Factor

x^{2} - x y + 4 x - 4 y : (x - y) (x + 4)

= \frac{( x - y ) ( x + 4 )}{x ^{2} - 2 x y + y ^{2}}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

x^{2} - 2 x y + y^{2} = (x - y)^{2}

= \frac{( x - y ) ( x + 4 )}{( x - y ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x - y)^{2} = (x - y) (x - y)

= \frac{( x - y ) ( x + 4 )}{( x - y ) ( x - y )}

Cancel the common factor:

x - y

= \frac{x + 4}{x - y}

\frac{2 π}{\frac{5}{6}}

\frac{x ^{2} + 4 x - 12}{x ^{2} ( x ^{2} + 9 x + 18 )} \cdot 6 x^{2}

2^{- 1} + 2^{- 2}

6 (ab + a^{2}) - 5 (a^{2} - ab) + 2 (ba - a^{2})

\frac{240}{360}

What is (x^2-xy+4x-4y)/(x^2-2xy+y^2) ?
The solution to (x^2-xy+4x-4y)/(x^2-2xy+y^2) is (x+4)/(x-y)