What is expand (x-3)(2x+1)(3x-2) ?

The solution to expand (x-3)(2x+1)(3x-2) is 6x^3-19x^2+x+6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x-3)(2x+1)(3x-2)

expand

(x - 3) (2 x + 1) (3 x - 2)

6 x^{3} - 19 x^{2} + x + 6

Solution steps

(x - 3) (2 x + 1) (3 x - 2)

Expand

(x - 3) (2 x + 1) (3 x - 2) : (2 x^{2} - 5 x - 3) (3 x - 2)

= (2 x^{2} - 5 x - 3) (3 x - 2)

Distribute parentheses

= 2 x^{2} \cdot 3 x + 2 x^{2} (- 2) - 5 x \cdot 3 x - 5 x (- 2) - 3 \cdot 3 x - 3 (- 2)

Simplify

2 x^{2} \cdot 3 x + 2 x^{2} (- 2) - 5 x \cdot 3 x - 5 x (- 2) - 3 \cdot 3 x - 3 (- 2) : 6 x^{3} - 19 x^{2} + x + 6

= 6 x^{3} - 19 x^{2} + x + 6

3^{4} \cdot 3^{5}

\frac{x ^{4} - 1}{x ^{3} - 1}

(x - 2) (x - 3) (x - 4) (x - 5)

15 - 4 (\frac{3}{2} x + 8)

(x^{2} - 3 x + 2)^{2}

What is expand (x-3)(2x+1)(3x-2) ?
The solution to expand (x-3)(2x+1)(3x-2) is 6x^3-19x^2+x+6