What is (3+ki)(6-3i) ?

The solution to (3+ki)(6-3i) is (18+3k)+(-9+6k)i

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simplify (3+ki)(6-3i)

simplify

(3 + ki) (6 - 3 i)

(18 + 3 k) + (- 9 + 6 k) i

Solution steps

(3 + ki) (6 - 3 i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= (3 \cdot 6 - k (- 3)) + (3 (- 3) + k \cdot 6) i

Simplify

(3 \cdot 6 - k (- 3)) + (3 (- 3) + k \cdot 6) i : (18 + 3 k) + (- 9 + k \cdot 6) i

= (18 + 3 k) + (- 9 + k \cdot 6) i

= (18 + 3 k) + (- 9 + 6 k) i

\frac{a}{a - 1} - \frac{5}{1 - a}

1 + \frac{1}{x + 1}

1 - \frac{sin ( x )}{cos ( x )}

(2 x^{2} + 1) - (x^{2} - 2 x + 1)

\frac{\frac{6 x + 6}{7}}{\frac{4 x + 4}{x - 2}}