What are the solutions to the equation 2y^2-96=0 ?

The solutions to the equation 2y^2-96=0 are y=4sqrt(3),y=-4sqrt(3)

Find the zeros of 2y^2-96=0

The zeros of 2y^2-96=0 are y=4sqrt(3),y=-4sqrt(3)

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2 y^{2} - 96 = 0

y = 43, y = - 43

Solution steps

2 y^{2} - 96 = 0

Move

96

to the right side

2 y^{2} = 96

Divide both sides by

2

y^{2} = 48

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 48, y = - 48

48 = 43

- 48 = - 43

y = 43, y = - 43

5 x^{2} + 10 x + 5 = 0

∣ 5 a - 1 ∣ = 9

(4^{- 4})^{2}

\frac{1 + \frac{2}{c - 1}}{1 - \frac{2}{c - 1}}

x^{2} - 35 x + 300 = 0

What are the solutions to the equation 2y^2-96=0 ?
The solutions to the equation 2y^2-96=0 are y=4sqrt(3),y=-4sqrt(3)
Find the zeros of 2y^2-96=0
The zeros of 2y^2-96=0 are y=4sqrt(3),y=-4sqrt(3)