What is expand (x(x-1)(x-2))/6 ?

The solution to expand (x(x-1)(x-2))/6 is (x^3)/6-(x^2)/2+x/3

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expand (x(x-1)(x-2))/6

expand

\frac{x ( x - 1 ) ( x - 2 )}{6}

\frac{x ^{3}}{6} - \frac{x ^{2}}{2} + \frac{x}{3}

Solution steps

\frac{x ( x - 1 ) ( x - 2 )}{6}

Expand

x (x - 1) (x - 2) : x^{3} - 3 x^{2} + 2 x

= \frac{x ^{3} - 3 x ^{2} + 2 x}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 3 x ^{2} + 2 x}{6} = \frac{x ^{3}}{6} - \frac{3 x ^{2}}{6} + \frac{2 x}{6}

= \frac{x ^{3}}{6} - \frac{3 x ^{2}}{6} + \frac{2 x}{6}

Cancel

\frac{3 x ^{2}}{6} : \frac{x ^{2}}{2}

= \frac{x ^{3}}{6} - \frac{x ^{2}}{2} + \frac{2 x}{6}

Cancel

\frac{2 x}{6} : \frac{x}{3}

= \frac{x ^{3}}{6} - \frac{x ^{2}}{2} + \frac{x}{3}

(e - 5) (f - 2 g)

\frac{1 + x - 4 x ^{2}}{( 1 - x ) ^{2} ( 1 + 2 x )}

\frac{13 ( x - 1 )}{( 5 - 2 x ) ( 3 x - 1 )}

\frac{2 x ^{3} - 1}{( 2 x ^{4} - 4 x ) ^{3}}

\frac{( 3 - x ) ^{2}}{9}

What is expand (x(x-1)(x-2))/6 ?
The solution to expand (x(x-1)(x-2))/6 is (x^3)/6-(x^2)/2+x/3