What is expand (1-x^2)p''(x)-2xp'(x) ?

The solution to expand (1-x^2)p''(x)-2xp'(x) is p''(x)-x^2p''(x)-2xp'(x)

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expand (1-x^2)p''(x)-2xp'(x)

expand

(1 - x^{2}) p^{''} (x) - 2 x p^{'} (x)

p'' (x) - x^{2} p'' (x) - 2 x p' (x)

Solution steps

(1 - x^{2}) p^{''} (x) - 2 x p^{'} (x)

Expand

p^{''} (x) (1 - x^{2}) : p^{''} (x) - x^{2} p^{''} (x)

= p^{''} (x) - x^{2} p^{''} (x) - 2 x p^{'} (x)

3 (e - 1)

\frac{( k - 1 ) x ^{2} + k x + 1}{( x + 3 )}

- 3 (x + y t) e^{- 3 t} + 2 (y) e^{- 3 t}

(e^{x} + 3) (sin (x) + ln (x))

\frac{x ( 4 x - 3 )}{2}

What is expand (1-x^2)p''(x)-2xp'(x) ?
The solution to expand (1-x^2)p''(x)-2xp'(x) is p''(x)-x^2p''(x)-2xp'(x)