What is expand sin(x)+1/(2pi)(x/(2pi)-1) ?

The solution to expand sin(x)+1/(2pi)(x/(2pi)-1) is sin(x)+x/(4pi^2)-1/(2pi)

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expand sin(x)+1/(2pi)(x/(2pi)-1)

expand

sin (x) + \frac{1}{2 π} (\frac{x}{2 π} - 1)

sin (x) + \frac{x}{4 π ^{2}} - \frac{1}{2 π}

Solution steps

sin (x) + \frac{1}{2 π} (\frac{x}{2 π} - 1)

Expand

\frac{1}{2 π} (\frac{x}{2 π} - 1) : \frac{x}{4 π ^{2}} - \frac{1}{2 π}

= sin (x) + \frac{x}{4 π ^{2}} - \frac{1}{2 π}

- sin ((k + \frac{1}{2}) π)

(x) (\frac{( 96 - 16 x )}{12})^{2}

- 2 (e^{x} + e^{x} x)

\frac{( x + 3 ) ^{4}}{4}

\frac{3 x + 5}{( x + 2 ) ^{2} ( x ^{2} + 2 )}

What is expand sin(x)+1/(2pi)(x/(2pi)-1) ?
The solution to expand sin(x)+1/(2pi)(x/(2pi)-1) is sin(x)+x/(4pi^2)-1/(2pi)