What is expand (-1)/3 (x^2+2(-5)x+(-5)^2+(-4)=0) ?

The solution to expand (-1)/3 (x^2+2(-5)x+(-5)^2+(-4)=0) is -(x^2)/3+(10x)/3-7=0

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expand (-1)/3 (x^2+2(-5)x+(-5)^2+(-4)=0)

expand

\frac{- 1}{3} (x^{2} + 2 (- 5) x + (- 5)^{2} + (- 4) = 0)

- \frac{x ^{2}}{3} + \frac{10 x}{3} - 7 = 0

Solution steps

\frac{- 1}{3} (x^{2} + 2 (- 5) x + (- 5)^{2} + (- 4) = 0)

= \frac{- 1}{3} (x^{2} + 2 (- 5) x + (- 5)^{2} + (- 4) \cdot 0 =)

Distribute parentheses

\frac{- 1}{3} x^{2} + \frac{- 1}{3} \cdot 2 (- 5) x + \frac{- 1}{3} (- 5)^{2} + \frac{- 1}{3} (- 4) = 0

\frac{- 1}{3} x^{2} + 2 (- 5) \frac{- 1}{3} x + (- 5)^{2} \frac{- 1}{3} + (- 4) \frac{- 1}{3} = 0

Expand

\frac{- 1}{3} x^{2} + 2 (- 5) \frac{- 1}{3} x + (- 5)^{2} \frac{- 1}{3} + (- 4) \frac{- 1}{3} : - \frac{x ^{2}}{3} + \frac{10 x}{3} - 7

- \frac{x ^{2}}{3} + \frac{10 x}{3} - 7 = 0

\frac{2 ( 2 5 - 2 2 )}{3}

((n + 1)! (n + 2)) - 1

(y - x) d x + (y + x) d y

((x + 1) - (e^{8 x - 8}))^{2}

\frac{1}{( x ^{2} + 1 ) ( x + 2 )}

What is expand (-1)/3 (x^2+2(-5)x+(-5)^2+(-4)=0) ?
The solution to expand (-1)/3 (x^2+2(-5)x+(-5)^2+(-4)=0) is -(x^2)/3+(10x)/3-7=0