What is expand 6(3x-10=5(2x+15)) ?

The solution to expand 6(3x-10=5(2x+15)) is 18x-60=10x+75

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expand 6(3x-10=5(2x+15))

expand

6 (3 x - 10 = 5 (2 x + 15))

18 x - 60 = 10 x + 75

Solution steps

6 (3 x - 10 = 5 (2 x + 15))

= 6 (3 x - 10 \cdot 5 = (2 x + 15))

Apply the distributive law:

a (b - c) = ab - a c

a = 6, b = 3 x, c = 10 = 5 (2 x + 15)

6 \cdot 3 x - 6 \cdot 10 = 5 (2 x + 15)

Simplify

6 \cdot 3 x - 6 \cdot 10 = 5 (2 x + 15) : 18 x - 60 = 10 x + 75

18 x - 60 = 10 x + 75

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\frac{2}{x ( x ^{2} - 16 )}

f (x) = \frac{2 x ^{5} + 28 x ^{3} - 6 x}{( x ^{2} - 1 ) ^{4}}

\frac{100 a ^{2} - 20 a + 1}{100}

What is expand 6(3x-10=5(2x+15)) ?
The solution to expand 6(3x-10=5(2x+15)) is 18x-60=10x+75