What is expand 1/2 (e^x+e^{2-x}) ?

The solution to expand 1/2 (e^x+e^{2-x}) is 1/2 e^x+1/2 e^{2-x}

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expand 1/2 (e^x+e^{2-x})

expand

\frac{1}{2} (e^{x} + e^{2 - x})

\frac{1}{2} e^{x} + \frac{1}{2} e^{2 - x}

Solution steps

\frac{1}{2} (e^{x} + e^{2 - x})

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{1}{2}, b = e^{x}, c = e^{2 - x}

= \frac{1}{2} e^{x} + \frac{1}{2} e^{2 - x}

\frac{( 16 x ^{2} - 1 ) ^{2}}{64 x ^{2}}

- \frac{10 x ^{2} + 6}{( x ^{2} + x + 1 ) ( x ^{2} - x + 1 )}

- \frac{3}{( s + 2 ) ( s + 1 )}

(x^{2} + 2)^{12}

(x - 1)^{2} (e^{x} - 1)

What is expand 1/2 (e^x+e^{2-x}) ?
The solution to expand 1/2 (e^x+e^{2-x}) is 1/2 e^x+1/2 e^{2-x}