What are the solutions to the equation 3-3(4-x)^2=18 ?

The solutions to the equation 3-3(4-x)^2=18 are x=-sqrt(5)i+4,x=sqrt(5)i+4

Find the zeros of 3-3(4-x)^2=18

The zeros of 3-3(4-x)^2=18 are x=-sqrt(5)i+4,x=sqrt(5)i+4

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3 - 3 (4 - x)^{2} = 18

x = - 5 i + 4, x = 5 i + 4

Solution steps

3 - 3 (4 - x)^{2} = 18

Move

3

to the right side

- 3 (4 - x)^{2} = 15

Divide both sides by

- 3

(4 - x)^{2} = - 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 - x = - 5 : x = - 5 i + 4

Solve

4 - x = - - 5 : x = 5 i + 4

The solutions to the quadratic equation are:

x = - 5 i + 4, x = 5 i + 4

49 x^{2} + 25 = 70 x

3 (x - y)^{2} + 2 y (x - y) - 5 y^{2}

\frac{2}{3} (\frac{x}{8} - \frac{3}{4}) = \frac{x}{2} - \frac{1}{12}

(x - 7) (4 - x) (x + 1) \geq 0

\frac{0.9273}{\frac{π}{45}}

What are the solutions to the equation 3-3(4-x)^2=18 ?
The solutions to the equation 3-3(4-x)^2=18 are x=-sqrt(5)i+4,x=sqrt(5)i+4
Find the zeros of 3-3(4-x)^2=18
The zeros of 3-3(4-x)^2=18 are x=-sqrt(5)i+4,x=sqrt(5)i+4