What is expand-(2(-x^2+x+3))/(e^x) ?

The solution to expand-(2(-x^2+x+3))/(e^x) is (2x^2)/(e^x)-(2x)/(e^x)-6/(e^x)

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expand-(2(-x^2+x+3))/(e^x)

expand

- \frac{2 ( - x ^{2} + x + 3 )}{e ^{x}}

\frac{2 x ^{2}}{e ^{x}} - \frac{2 x}{e ^{x}} - \frac{6}{e ^{x}}

Solution steps

- \frac{2 ( - x ^{2} + x + 3 )}{e ^{x}}

Expand

2 (- x^{2} + x + 3) : - 2 x^{2} + 2 x + 6

= - \frac{- 2 x ^{2} + 2 x + 6}{e ^{x}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 2 x ^{2} + 2 x + 6}{e ^{x}} = - (- \frac{2 x ^{2}}{e ^{x}}) - (\frac{2 x}{e ^{x}}) - (\frac{6}{e ^{x}})

= - (- \frac{2 x ^{2}}{e ^{x}}) - (\frac{2 x}{e ^{x}}) - (\frac{6}{e ^{x}})

Remove parentheses:

(a) = a, - (- a) = a

= \frac{2 x ^{2}}{e ^{x}} - \frac{2 x}{e ^{x}} - \frac{6}{e ^{x}}

\frac{1}{( ( x - 3 ) ( x - 2 ) )}

(sin (x) - 1) ln (tan (x))

a (25, 12) b (6, - 13)

\frac{1}{( 1 - b z ) ( 1 - a z )}

e^{x} (- x e^{- x} - e^{- x})

What is expand-(2(-x^2+x+3))/(e^x) ?
The solution to expand-(2(-x^2+x+3))/(e^x) is (2x^2)/(e^x)-(2x)/(e^x)-6/(e^x)