What is expand (9e^{3x})/((e^{3x)+1)^2} ?

The solution to expand (9e^{3x})/((e^{3x)+1)^2} is (9e^{3x})/(e^{6x)+2e^{3x}+1}

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expand (9e^{3x})/((e^{3x)+1)^2}

expand

\frac{9 e ^{3 x}}{( e ^{3 x} + 1 ) ^{2}}

\frac{9 e ^{3 x}}{e ^{6 x} + 2 e ^{3 x} + 1}

Solution steps

\frac{9 e ^{3 x}}{( e ^{3 x} + 1 ) ^{2}}

(e^{3 x} + 1)^{2} = e^{6 x} + 2 e^{3 x} + 1

= \frac{9 e ^{3 x}}{e ^{6 x} + 2 e ^{3 x} + 1}

1 + x^{2} \frac{d y}{d x} - x (2 + y)

\frac{3}{x + 1} + \frac{7}{x - 4} - \frac{5}{x + 5}

\frac{2 y}{1 + ( x + y ^{2} ) ^{2}}

(e^{2 x} - e^{- 3 x})^{3}

(9 \cdot e^{- 9 \cdot x} + 2)^{3}

What is expand (9e^{3x})/((e^{3x)+1)^2} ?
The solution to expand (9e^{3x})/((e^{3x)+1)^2} is (9e^{3x})/(e^{6x)+2e^{3x}+1}