What is expand ((x+1)^2(x-5))/((x-1)^3) ?

The solution to expand ((x+1)^2(x-5))/((x-1)^3) is (x^3-3x^2-9x-5)/(x^3-3x^2+3x-1)

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expand ((x+1)^2(x-5))/((x-1)^3)

expand

\frac{( x + 1 ) ^{2} ( x - 5 )}{( x - 1 ) ^{3}}

\frac{x ^{3} - 3 x ^{2} - 9 x - 5}{x ^{3} - 3 x ^{2} + 3 x - 1}

Solution steps

\frac{( x + 1 ) ^{2} ( x - 5 )}{( x - 1 ) ^{3}}

(x - 1)^{3} = x^{3} - 3 x^{2} + 3 x - 1

= \frac{( x + 1 ) ^{2} ( x - 5 )}{x ^{3} - 3 x ^{2} + 3 x - 1}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{( x ^{2} + 2 x + 1 ) ( x - 5 )}{x ^{3} - 3 x ^{2} + 3 x - 1}

Expand

(x^{2} + 2 x + 1) (x - 5) : x^{3} - 3 x^{2} - 9 x - 5

= \frac{x ^{3} - 3 x ^{2} - 9 x - 5}{x ^{3} - 3 x ^{2} + 3 x - 1}

\frac{2 e ^{- 2 s} ( 2 s ^{2} + 2 s + 1 )}{s ^{3}}

\frac{b}{n ( b - g - u )} + \frac{c}{e ^{t (b - g - u)}}

- \frac{4 ( 9 y ^{2} + 4 x ^{2} )}{81 y ^{3}}

\frac{1}{( x - a ) ^{3}} - \frac{1}{( x + a ) ^{2}}

\frac{s + 1}{( s ^{2} + 2 s + 10 ) ^{2}}

What is expand ((x+1)^2(x-5))/((x-1)^3) ?
The solution to expand ((x+1)^2(x-5))/((x-1)^3) is (x^3-3x^2-9x-5)/(x^3-3x^2+3x-1)