What is expand ((x+2)(x-3))/((x-2)(x-1)) ?

The solution to expand ((x+2)(x-3))/((x-2)(x-1)) is (x^2-x-6)/(x^2-3x+2)

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expand ((x+2)(x-3))/((x-2)(x-1))

expand

\frac{( x + 2 ) ( x - 3 )}{( x - 2 ) ( x - 1 )}

\frac{x ^{2} - x - 6}{x ^{2} - 3 x + 2}

Solution steps

\frac{( x + 2 ) ( x - 3 )}{( x - 2 ) ( x - 1 )}

Expand

(x - 2) (x - 1) : x^{2} - 3 x + 2

= \frac{( x + 2 ) ( x - 3 )}{x ^{2} - 3 x + 2}

Expand

(x + 2) (x - 3) : x^{2} - x - 6

= \frac{x ^{2} - x - 6}{x ^{2} - 3 x + 2}

\frac{K}{( J s + b ) ( L s + R ) + K ^{2}}

\frac{x ( x - 2 )}{( x + 3 ) ( x - 4 ) ^{2}}

\frac{( 3 x + 4 ) ^{3}}{3}

(1 + e^{x}) y^{'} (x)

ln (x) (x - ln (x)) + 1

What is expand ((x+2)(x-3))/((x-2)(x-1)) ?
The solution to expand ((x+2)(x-3))/((x-2)(x-1)) is (x^2-x-6)/(x^2-3x+2)