What is expand 4+f(2t-7)\H(t-2) ?

The solution to expand 4+f(2t-7)\H(t-2) is 4+2ft\H(t-2)-7f\H(t-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 4+f(2t-7)\H(t-2)

expand

4 + f (2 t - 7) H (t - 2)

4 + 2 f t H (t - 2) - 7 f H (t - 2)

Solution steps

4 + f (2 t - 7) H (t - 2)

= 4 + f H (t - 2) (2 t - 7)

Expand

f H (t - 2) (2 t - 7) : 2 f t H (t - 2) - 7 f H (t - 2)

= 4 + 2 f t H (t - 2) - 7 f H (t - 2)

\frac{2}{3} n - \frac{1}{4}

\frac{x ( x - 1 )}{( x - 2 ) ( x - 4 )}

- 6 (- 6 e^{(- 3 x^{2})} (x^{2}) + e^{(- 3 x^{2})})

ln (\frac{x - 4}{( y - 5 ) ( z + 3 ) ^{3}})

\frac{4 ( 10 - 1 )}{3}

What is expand 4+f(2t-7)\H(t-2) ?
The solution to expand 4+f(2t-7)\H(t-2) is 4+2ft\H(t-2)-7f\H(t-2)