What is expand (x(x-1))/((x-2)(x-4)) ?

The solution to expand (x(x-1))/((x-2)(x-4)) is (x^2-x)/(x^2-6x+8)

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expand (x(x-1))/((x-2)(x-4))

expand

\frac{x ( x - 1 )}{( x - 2 ) ( x - 4 )}

\frac{x ^{2} - x}{x ^{2} - 6 x + 8}

Solution steps

\frac{x ( x - 1 )}{( x - 2 ) ( x - 4 )}

Expand

(x - 2) (x - 4) : x^{2} - 6 x + 8

= \frac{x ( x - 1 )}{x ^{2} - 6 x + 8}

Expand

x (x - 1) : x^{2} - x

= \frac{x ^{2} - x}{x ^{2} - 6 x + 8}

- 6 (- 6 e^{(- 3 x^{2})} (x^{2}) + e^{(- 3 x^{2})})

ln (\frac{x - 4}{( y - 5 ) ( z + 3 ) ^{3}})

\frac{4 ( 10 - 1 )}{3}

320 (\frac{x}{16} + \frac{x}{20} = 1)

\frac{7 x ^{2}}{( x - 4 ) ( x + 7 )}

What is expand (x(x-1))/((x-2)(x-4)) ?
The solution to expand (x(x-1))/((x-2)(x-4)) is (x^2-x)/(x^2-6x+8)