What are the solutions to the equation x^2+2x=12 ?

The solutions to the equation x^2+2x=12 are x=-1+sqrt(13),x=-1-sqrt(13)

Find the zeros of x^2+2x=12

The zeros of x^2+2x=12 are x=-1+sqrt(13),x=-1-sqrt(13)

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x^{2} + 2 x = 12

x = - 1 + 13, x = - 1 - 13

Solution steps

x^{2} + 2 x = 12

Move

12

to the left side

x^{2} + 2 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 12) = 213

x_{1, 2} = \frac{- 2 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 13}{2 \cdot 1}

x = \frac{- 2 + 2 13}{2 \cdot 1} : - 1 + 13

x = \frac{- 2 - 2 13}{2 \cdot 1} : - 1 - 13

The solutions to the quadratic equation are:

x = - 1 + 13, x = - 1 - 13

x^{4} + 2 x^{2} + x

\frac{6}{5} + 1

15 x^{3} + 35 x^{2} + 20 x \geq 0

5 x^{2} + 26 x - 24 = 0

3 y^{3} - 2 y^{2} + 21 y - 14

What are the solutions to the equation x^2+2x=12 ?
The solutions to the equation x^2+2x=12 are x=-1+sqrt(13),x=-1-sqrt(13)
Find the zeros of x^2+2x=12
The zeros of x^2+2x=12 are x=-1+sqrt(13),x=-1-sqrt(13)