What is 15x^3+35x^2+20x>= 0 ?

The solution to 15x^3+35x^2+20x>= 0 is -4/3 = 0

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15x^3+35x^2+20x>= 0

15 x^{3} + 35 x^{2} + 20 x \geq 0

- \frac{4}{3} \leq x \leq - 1 or x \geq 0

Interval Notation

[- \frac{4}{3}, - 1] \cup [0, \infty)

Decimal Notation

- 1.33333 \dots \leq x \leq - 1 or x \geq 0

Solution steps

15 x^{3} + 35 x^{2} + 20 x \geq 0

Rewrite in standard form

3 x^{3} + 7 x^{2} + 4 x \geq 0

Factor

3 x^{3} + 7 x^{2} + 4 x : x (x + 1) (3 x + 4)

x (x + 1) (3 x + 4) \geq 0

Identify the intervals

- \frac{4}{3} \leq x \leq - 1 or x \geq 0

5 x^{2} + 26 x - 24 = 0

3 y^{3} - 2 y^{2} + 21 y - 14

65 Q - \frac{Q ^{2}}{100} - (722 + \frac{Q ^{2}}{200}) = 0

\frac{1}{5} + \frac{1}{12}

u^{2} - 9 u + 18 = 0

What is 15x^3+35x^2+20x>= 0 ?
The solution to 15x^3+35x^2+20x>= 0 is -4/3 <= x<=-1\lor x>= 0