What is expand (d(d-1)(d-2))/6 ?

The solution to expand (d(d-1)(d-2))/6 is (d^3)/6-(d^2)/2+d/3

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expand (d(d-1)(d-2))/6

expand

\frac{d ( d - 1 ) ( d - 2 )}{6}

\frac{d ^{3}}{6} - \frac{d ^{2}}{2} + \frac{d}{3}

Solution steps

\frac{d ( d - 1 ) ( d - 2 )}{6}

Expand

d (d - 1) (d - 2) : d^{3} - 3 d^{2} + 2 d

= \frac{d ^{3} - 3 d ^{2} + 2 d}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{d ^{3} - 3 d ^{2} + 2 d}{6} = \frac{d ^{3}}{6} - \frac{3 d ^{2}}{6} + \frac{2 d}{6}

= \frac{d ^{3}}{6} - \frac{3 d ^{2}}{6} + \frac{2 d}{6}

Cancel

\frac{3 d ^{2}}{6} : \frac{d ^{2}}{2}

= \frac{d ^{3}}{6} - \frac{d ^{2}}{2} + \frac{2 d}{6}

Cancel

\frac{2 d}{6} : \frac{d}{3}

= \frac{d ^{3}}{6} - \frac{d ^{2}}{2} + \frac{d}{3}

\frac{1}{( s + 1 ) ( s + 3 ) ( s + 5 )}

\frac{7 x}{( 2 x + 1 ) ( x - 3 )}

\frac{2 ( 3 e ^{3 π} + 1 ) ( 3 e ^{3 π} - 1 )}{e ^{6 π}}

\frac{4 x ^{3}}{( x + 1 ) ^{2} ( x ^{2} - 1 )}

1576 x ((2, \frac{5}{2}) - 1)

What is expand (d(d-1)(d-2))/6 ?
The solution to expand (d(d-1)(d-2))/6 is (d^3)/6-(d^2)/2+d/3