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Popular >

expand (3x+3)(x+1)'

Solution

expand

(3 x + 3) (x + 1)^{'}

Solution

3 x (x + 1)' + 3 (x + 1)'

Solution steps

(3 x + 3) (x + 1)^{'}

Apply the distributive law:

a (b + c) = ab + a c

a = (x + 1)^{'}, b = 3 x, c = 3

= (x + 1)^{^{'}} 3 x + (x + 1)^{^{'}} 3

= 3 x (x + 1)^{^{'}} + 3 (x + 1)^{^{'}}

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Frequently Asked Questions (FAQ)

What is expand (3x+3)(x+1)' ?
The solution to expand (3x+3)(x+1)' is 3x(x+1)'+3(x+1)'