What is expand log_{9}(sqrt(23)) ?

The solution to expand log_{9}(sqrt(23)) is 1/2 log_{9}(23)

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expand log_{9}(sqrt(23))

expand

lo g_{9} (23)

\frac{1}{2} lo g_{9} (23)

Decimal Notation

0.71351 \dots

Solution steps

lo g_{9} (23)

Rewrite as

= lo g_{9} (2 3^{\frac{1}{2}})

Apply log rule

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x),

assuming

x \geq 0

= \frac{1}{2} lo g_{9} (23)

(f \circ g) (x^{2} - 1) (2 x + 5)

\frac{x}{( x + 1 ) ( x ^{2} + 1 )}

\frac{x + 1}{5 x ( x + 3 )}

\frac{1}{z ( z ^{2} + 1 )}

\frac{e ^{- 4 x}}{( x + 3 ) ( x - 9 )}

What is expand log_{9}(sqrt(23)) ?
The solution to expand log_{9}(sqrt(23)) is 1/2 log_{9}(23)