What is expand ((x+2)^3)/6 ?

The solution to expand ((x+2)^3)/6 is (x^3)/6+x^2+2x+4/3

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expand ((x+2)^3)/6

expand

\frac{( x + 2 ) ^{3}}{6}

\frac{x ^{3}}{6} + x^{2} + 2 x + \frac{4}{3}

Solution steps

\frac{( x + 2 ) ^{3}}{6}

(x + 2)^{3} = x^{3} + 6 x^{2} + 12 x + 8

= \frac{x ^{3} + 6 x ^{2} + 12 x + 8}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 6 x ^{2} + 12 x + 8}{6} = \frac{x ^{3}}{6} + \frac{6 x ^{2}}{6} + \frac{12 x}{6} + \frac{8}{6}

= \frac{x ^{3}}{6} + \frac{6 x ^{2}}{6} + \frac{12 x}{6} + \frac{8}{6}

Divide the numbers:

\frac{6}{6} = 1

= \frac{x ^{3}}{6} + x^{2} + \frac{12 x}{6} + \frac{8}{6}

Divide the numbers:

\frac{12}{6} = 2

= \frac{x ^{3}}{6} + x^{2} + 2 x + \frac{8}{6}

Cancel

\frac{8}{6} : \frac{4}{3}

= \frac{x ^{3}}{6} + x^{2} + 2 x + \frac{4}{3}

\frac{( a + d + ( a - d ) ^{2} + 4 b c ) ^{2}}{4}

\frac{( x - 4 ) ( x + 2 )}{( x + 1 ) ( x - 6 )}

\frac{4}{3} π (\frac{3 a ^{2} b ^{4} - 2 a ^{4} b}{2})^{3}

\frac{x ( 6 x ^{3} + 15 x - 1 )}{3}

\frac{( 90 - 3 x ) ( 5 x + 15 )}{2}

What is expand ((x+2)^3)/6 ?
The solution to expand ((x+2)^3)/6 is (x^3)/6+x^2+2x+4/3