What is expand (4x^2-4x+12)/(x(x+3)(x+4)) ?

The solution to expand (4x^2-4x+12)/(x(x+3)(x+4)) is (4x^2-4x+12)/(x^3+7x^2+12x)

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expand (4x^2-4x+12)/(x(x+3)(x+4))

expand

\frac{4 x ^{2} - 4 x + 12}{x ( x + 3 ) ( x + 4 )}

\frac{4 x ^{2} - 4 x + 12}{x ^{3} + 7 x ^{2} + 12 x}

Solution steps

\frac{4 x ^{2} - 4 x + 12}{x ( x + 3 ) ( x + 4 )}

Expand

x (x + 3) (x + 4) : x^{3} + 7 x^{2} + 12 x

= \frac{4 x ^{2} - 4 x + 12}{x ^{3} + 7 x ^{2} + 12 x}

\frac{d}{d q} ((r (q, x)) (12.5 + 0.02 x))

ln (w + x) \cdot p + ln (w - x) \cdot (1 - p)

\frac{7 x}{( 2 x + 1 ) ( x - 3 ) d x}

(e - 4)^{2}

\frac{12 ( x - 2 ) ^{2}}{6 ( x - 2 ) x + 5}

What is expand (4x^2-4x+12)/(x(x+3)(x+4)) ?
The solution to expand (4x^2-4x+12)/(x(x+3)(x+4)) is (4x^2-4x+12)/(x^3+7x^2+12x)