What is expand dx(e^{sin(x)}+cos(x)) ?

The solution to expand dx(e^{sin(x)}+cos(x)) is e^{sin(x)}dx+cos(x)dx

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand dx(e^{sin(x)}+cos(x))

expand

d x (e^{s i n (x)} + cos (x))

e^{s i n (x)} d x + cos (x) d x

Solution steps

d x (e^{s i n (x)} + cos (x))

Apply the distributive law:

a (b + c) = ab + a c

a = d x, b = e^{s i n (x)}, c = cos (x)

= d x e^{s i n (x)} + d x cos (x)

= e^{s i n (x)} d x + cos (x) d x

(x - 1)^{2 \circ} (x + 1)

(3 x + 2 y = 1, 6) (y = - 7 x + 19)

(e^{x} cos (x) - sin (x) e^{x}) (- 2 e^{x} sin (x))

\frac{( x + 1 )}{2 x ( 2 x + 1 )}

(x - y)^{2} ((x - y) - Δ)

What is expand dx(e^{sin(x)}+cos(x)) ?
The solution to expand dx(e^{sin(x)}+cos(x)) is e^{sin(x)}dx+cos(x)dx