What is expand (3x+2y=1,6)(y=-7x+19) ?

The solution to expand (3x+2y=1,6)(y=-7x+19) is 3xy=-3*7xx+3*19x+2y=1,6y=-2y=1,6*7x+2y=1,6*19

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expand (3x+2y=1,6)(y=-7x+19)

expand

(3 x + 2 y = 1, 6) (y = - 7 x + 19)

3 x y = - 3 \cdot 7 xx + 3 \cdot 19 x + 2 y = 1, 6 y = - 2 y = 1, 6 \cdot 7 x + 2 y = 1, 6 \cdot 19

Solution steps

(3 x + 2 y = 1, 6) (y = - 7 x + 19)

= (3 x + 2 \cdot 1 \cdot 6 =, y) (= y - 7 x + 19)

Distribute parentheses

3 x y = 3 x (- 7 x) + 3 x \cdot 19 + 2 y = 1, 6 y = 2 y = 1, 6 (- 7 x) + 2 y = 1, 6 \cdot 19

Apply minus-plus rules

+ (- a) = - a

3 x y = - 3 \cdot 7 xx + 3 \cdot 19 x + 2 y = 1, 6 y = - 2 y = 1, 6 \cdot 7 x + 2 y = 1, 6 \cdot 19

(e^{x} cos (x) - sin (x) e^{x}) (- 2 e^{x} sin (x))

\frac{( x + 1 )}{2 x ( 2 x + 1 )}

(x - y)^{2} ((x - y) - Δ)

2 u y^{2} (y d u + u d y) + (y^{2} - 3 y^{2} v^{2}) d u

\frac{4 ( 3 ( 3 a + b ) - ( 5 a - b ) )}{12}

What is expand (3x+2y=1,6)(y=-7x+19) ?
The solution to expand (3x+2y=1,6)(y=-7x+19) is 3xy=-3*7xx+3*19x+2y=1,6y=-2y=1,6*7x+2y=1,6*19