What is expand (x-1)^{2\circ}(x+1) ?

The solution to expand (x-1)^{2\circ}(x+1) is x(x-1)^{2\circ}+(x-1)^{2\circ}

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expand (x-1)^{2\circ}(x+1)

expand

(x - 1)^{2 \circ} (x + 1)

x (x - 1)^{2 \circ} + (x - 1)^{2 \circ}

Solution steps

(x - 1)^{2 \circ} (x + 1)

= (x + 1) (x - 1)^{2 \circ}

Apply the distributive law:

a (b + c) = ab + a c

a = (x - 1)^{2 \circ}, b = x, c = 1

= (x - 1)^{2 \circ} x + (x - 1)^{2 \circ} \cdot 1

= x (x - 1)^{2 \circ} + 1 \cdot (x - 1)^{2 \circ}

Multiply:

1 \cdot (x - 1)^{2 \circ} = (x - 1)^{2 \circ}

= x (x - 1)^{2 \circ} + (x - 1)^{2 \circ}

(3 x + 2 y = 1, 6) (y = - 7 x + 19)

(e^{x} cos (x) - sin (x) e^{x}) (- 2 e^{x} sin (x))

\frac{( x + 1 )}{2 x ( 2 x + 1 )}

(x - y)^{2} ((x - y) - Δ)

2 u y^{2} (y d u + u d y) + (y^{2} - 3 y^{2} v^{2}) d u

What is expand (x-1)^{2\circ}(x+1) ?
The solution to expand (x-1)^{2\circ}(x+1) is x(x-1)^{2\circ}+(x-1)^{2\circ}