What is expand 2uy^2(ydu+udy)+(y^2-3y^2v^2)du ?

The solution to expand 2uy^2(ydu+udy)+(y^2-3y^2v^2)du is 2uy^3du+2u^2y^2dy+y^2du-3v^2y^2du

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expand 2uy^2(ydu+udy)+(y^2-3y^2v^2)du

expand

2 u y^{2} (y d u + u d y) + (y^{2} - 3 y^{2} v^{2}) d u

2 u y^{3} d u + 2 u^{2} y^{2} d y + y^{2} d u - 3 v^{2} y^{2} d u

Solution steps

2 u y^{2} (y d u + u d y) + (y^{2} - 3 y^{2} v^{2}) d u

= 2 u y^{2} (y d u + u d y) + (y^{2} - 3 v^{2} y^{2}) d u

Expand

2 u y^{2} (y d u + u d y) : 2 u y^{3} d u + 2 u^{2} y^{2} d y

= 2 u y^{3} d u + 2 u^{2} y^{2} d y + (y^{2} - 3 y^{2} v^{2}) d u

Expand

d u (y^{2} - 3 y^{2} v^{2}) : y^{2} d u - 3 v^{2} y^{2} d u

= 2 u y^{3} d u + 2 u^{2} y^{2} d y + y^{2} d u - 3 v^{2} y^{2} d u

\frac{4 ( 3 ( 3 a + b ) - ( 5 a - b ) )}{12}

, (x - 1) (x - 2) (x - 4)

(p + Δ p + 1)^{2}

\frac{( \frac{3 x}{2} )}{( \frac{3}{x} + 2 )}

(x + 5) + (x + 5) + (3 x - 2)

What is expand 2uy^2(ydu+udy)+(y^2-3y^2v^2)du ?
The solution to expand 2uy^2(ydu+udy)+(y^2-3y^2v^2)du is 2uy^3du+2u^2y^2dy+y^2du-3v^2y^2du