What is expand (2x^3+(-5-2i)x^2+(1+i)x+(2+i))/(2+i) ?

The solution to expand (2x^3+(-5-2i)x^2+(1+i)x+(2+i))/(2+i) is (2x^3-5x^2-2ix^2+x+ix+2+i)/(2+i)

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expand (2x^3+(-5-2i)x^2+(1+i)x+(2+i))/(2+i)

expand

\frac{2 x ^{3} + ( - 5 - 2 i ) x ^{2} + ( 1 + i ) x + ( 2 + i )}{2 + i}

\frac{2 x ^{3} - 5 x ^{2} - 2 i x ^{2} + x + i x + 2 + i}{2 + i}

Solution steps

\frac{2 x ^{3} + ( - 5 - 2 i ) x ^{2} + ( 1 + i ) x + ( 2 + i )}{2 + i}

Remove parentheses:

(a) = a

= \frac{2 x ^{3} + ( - 5 - 2 i ) x ^{2} + ( 1 + i ) x + 2 + i}{2 + i}

Expand

2 x^{3} + (- 5 - 2 i) x^{2} + (1 + i) x + 2 + i : 2 x^{3} - 5 x^{2} - 2 i x^{2} + x + i x + 2 + i

= \frac{2 x ^{3} - 5 x ^{2} - 2 i x ^{2} + x + i x + 2 + i}{2 + i}

a + (b + c)

1 + \frac{0.213 ( z + 0.8466 )}{( z - 1 ) ( z - 0.6065 )}

\frac{- 3 a ^{2} x ( a - x ) ^{2} - 3 x z ^{2} ( a - x ) ^{2}}{2}

π (- 128 ln (3) + \frac{808}{3})

- \frac{2 x}{2 x + 3} + ln ∣ 2 x + 3 ∣ - \frac{3}{2 ( 2 x + 3 )}

What is expand (2x^3+(-5-2i)x^2+(1+i)x+(2+i))/(2+i) ?
The solution to expand (2x^3+(-5-2i)x^2+(1+i)x+(2+i))/(2+i) is (2x^3-5x^2-2ix^2+x+ix+2+i)/(2+i)