What are the solutions to the equation 3x^2-7x-2=0 ?

The solutions to the equation 3x^2-7x-2=0 are x=(7+sqrt(73))/6 ,x=(7-sqrt(73))/6

Find the zeros of 3x^2-7x-2=0

The zeros of 3x^2-7x-2=0 are x=(7+sqrt(73))/6 ,x=(7-sqrt(73))/6

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3 x^{2} - 7 x - 2 = 0

x = \frac{7 + 73}{6}, x = \frac{7 - 73}{6}

Decimal Notation

x = 2.59066 \dots, x = - 0.25733 \dots

Solution steps

3 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 2) = 73

x_{1, 2} = \frac{- ( - 7 ) \pm 73}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 73}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 73}{2 \cdot 3}

x = \frac{- ( - 7 ) + 73}{2 \cdot 3} : \frac{7 + 73}{6}

x = \frac{- ( - 7 ) - 73}{2 \cdot 3} : \frac{7 - 73}{6}

The solutions to the quadratic equation are:

x = \frac{7 + 73}{6}, x = \frac{7 - 73}{6}

2 x (x + 3) + (3 - x)^{2} = 3 x (x + 1)

3 x^{2} - 9 = - 2 x

\frac{9}{- 5} + \frac{- 8}{7}

3 2^{\frac{6}{5}}

What are the solutions to the equation 3x^2-7x-2=0 ?
The solutions to the equation 3x^2-7x-2=0 are x=(7+sqrt(73))/6 ,x=(7-sqrt(73))/6
Find the zeros of 3x^2-7x-2=0
The zeros of 3x^2-7x-2=0 are x=(7+sqrt(73))/6 ,x=(7-sqrt(73))/6