What is expand 1/((1+e^x)e^{-x)} ?

The solution to expand 1/((1+e^x)e^{-x)} is 1/(e^{-x)+1}

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expand 1/((1+e^x)e^{-x)}

expand

\frac{1}{( 1 + e ^{x} ) e ^{- x}}

\frac{1}{e ^{- x} + 1}

Solution steps

\frac{1}{( 1 + e ^{x} ) e ^{- x}}

Expand

(1 + e^{x}) e^{- x} : e^{- x} + 1

= \frac{1}{e ^{- x} + 1}

2 π (\frac{π}{8} ln (2) - \frac{3}{4})

\frac{1}{( 2 n + 1 ) ^{2}}

\frac{1}{( x ^{2} - x + 1 ) ( x ^{2} + x + 1 )}

2^{b (x - c)^{2}}

(y - 1) (ln (y - 2) + 4)

What is expand 1/((1+e^x)e^{-x)} ?
The solution to expand 1/((1+e^x)e^{-x)} is 1/(e^{-x)+1}