What is expand 1/((x^2-x+1)(x^2+x+1)) ?

The solution to expand 1/((x^2-x+1)(x^2+x+1)) is 1/(x^4+x^2+1)

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expand 1/((x^2-x+1)(x^2+x+1))

expand

\frac{1}{( x ^{2} - x + 1 ) ( x ^{2} + x + 1 )}

\frac{1}{x ^{4} + x ^{2} + 1}

Solution steps

\frac{1}{( x ^{2} - x + 1 ) ( x ^{2} + x + 1 )}

Expand

(x^{2} - x + 1) (x^{2} + x + 1) : x^{4} + x^{2} + 1

= \frac{1}{x ^{4} + x ^{2} + 1}

2^{b (x - c)^{2}}

(y - 1) (ln (y - 2) + 4)

(x^{3} + x^{2} - x)^{10} + 2

\frac{1}{3} (- 1)^{3} + \frac{1}{2} (- 1)^{2} - 2 (- 1)

What is expand 1/((x^2-x+1)(x^2+x+1)) ?
The solution to expand 1/((x^2-x+1)(x^2+x+1)) is 1/(x^4+x^2+1)