What is expand ((16-a)/2)^2 ?

The solution to expand ((16-a)/2)^2 is (a^2)/4-8a+64

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expand ((16-a)/2)^2

expand

(\frac{16 - a}{2})^{2}

\frac{a ^{2}}{4} - 8 a + 64

Solution steps

(\frac{16 - a}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 16 - a ) ^{2}}{2 ^{2}}

(16 - a)^{2} = 256 - 32 a + a^{2}

= \frac{256 - 32 a + a ^{2}}{2 ^{2}}

2^{2} = 4

= \frac{256 - 32 a + a ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{256 - 32 a + a ^{2}}{4} = \frac{256}{4} - \frac{32 a}{4} + \frac{a ^{2}}{4}

= \frac{256}{4} - \frac{32 a}{4} + \frac{a ^{2}}{4}

Divide the numbers:

\frac{256}{4} = 64

= 64 - \frac{32 a}{4} + \frac{a ^{2}}{4}

Divide the numbers:

\frac{32}{4} = 8

= 64 - 8 a + \frac{a ^{2}}{4}

Rewrite in standard form

= \frac{a ^{2}}{4} - 8 a + 64

(a \cdot b^{'} + c) (a + b)

\frac{3}{2} (y = 1)^{2} - 3 y (y + 1)

\frac{x ^{2} - 1}{( 1 + x ^{2} ) ^{2}}

(- e^{x} - e^{- x}) \cdot (- e^{x} + e^{- x})

(5 x + 7) (x + 5)^{'}

What is expand ((16-a)/2)^2 ?
The solution to expand ((16-a)/2)^2 is (a^2)/4-8a+64