What is expand (p(x))/((x^2+1)^2(x-1)^2) ?

The solution to expand (p(x))/((x^2+1)^2(x-1)^2) is (px)/(x^6-2x^5+3x^4-4x^3+3x^2-2x+1)

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expand (p(x))/((x^2+1)^2(x-1)^2)

expand

\frac{p ( x )}{( x ^{2} + 1 ) ^{2} ( x - 1 ) ^{2}}

\frac{p x}{x ^{6} - 2 x ^{5} + 3 x ^{4} - 4 x ^{3} + 3 x ^{2} - 2 x + 1}

Solution steps

\frac{p ( x )}{( x ^{2} + 1 ) ^{2} ( x - 1 ) ^{2}}

Remove parentheses:

(a) = a

= \frac{p x}{( x ^{2} + 1 ) ^{2} ( x - 1 ) ^{2}}

(x^{2} + 1)^{2} = x^{4} + 2 x^{2} + 1

= \frac{p x}{( x ^{4} + 2 x ^{2} + 1 ) ( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{p x}{( x ^{4} + 2 x ^{2} + 1 ) ( x ^{2} - 2 x + 1 )}

Expand

(x^{4} + 2 x^{2} + 1) (x^{2} - 2 x + 1) : x^{6} - 2 x^{5} + 3 x^{4} - 4 x^{3} + 3 x^{2} - 2 x + 1

= \frac{p x}{x ^{6} - 2 x ^{5} + 3 x ^{4} - 4 x ^{3} + 3 x ^{2} - 2 x + 1}

\frac{( 12 x + 18 )}{x ( x ^{2} + 9 )}

(e^{j t} - e^{- j t})^{4}

sin (2 x) (1 - tan (2 x) = tan (2 x) cos (2 x))

P (- 1, 5) A (2, 1) y B (3, - 2)

8 x^{2} - 2 (- π^{225} + 2000) x + 625

What is expand (p(x))/((x^2+1)^2(x-1)^2) ?
The solution to expand (p(x))/((x^2+1)^2(x-1)^2) is (px)/(x^6-2x^5+3x^4-4x^3+3x^2-2x+1)