What is expand sin(2x)(1-tan(2x)=tan(2x)cos(2x)) ?

The solution to expand sin(2x)(1-tan(2x)=tan(2x)cos(2x)) is sin(2x)-sin(2x)tan(2x)=tan(2x)cos(2x)

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expand sin(2x)(1-tan(2x)=tan(2x)cos(2x))

expand

sin (2 x) (1 - tan (2 x) = tan (2 x) cos (2 x))

sin (2 x) - sin (2 x) tan (2 x) = tan (2 x) cos (2 x)

Solution steps

sin (2 x) (1 - tan (2 x) = tan (2 x) cos (2 x))

= sin (2 x) (1 - = tan (2 x) tan (2 x) cos (2 x))

Apply the distributive law:

a (b - c) = ab - a c

a = sin (2 x), b = 1, c = tan (2 x) = tan (2 x) cos (2 x)

sin (2 x) \cdot 1 - sin (2 x) tan (2 x) = tan (2 x) cos (2 x)

1 \cdot sin (2 x) - sin (2 x) tan (2 x) = tan (2 x) cos (2 x)

Expand

1 \cdot sin (2 x) - sin (2 x) tan (2 x) : sin (2 x) - sin (2 x) tan (2 x)

sin (2 x) - sin (2 x) tan (2 x) = tan (2 x) cos (2 x)

P (- 1, 5) A (2, 1) y B (3, - 2)

8 x^{2} - 2 (- π^{225} + 2000) x + 625

(x + 2 y - 1) (9 x + y^{'} (x) + 3)

\frac{x + 6}{( x + 7 ) ^{\frac{5}{4}}}

d u l u s (e^{- i x} + i e^{i x})^{2}

What is expand sin(2x)(1-tan(2x)=tan(2x)cos(2x)) ?
The solution to expand sin(2x)(1-tan(2x)=tan(2x)cos(2x)) is sin(2x)-sin(2x)tan(2x)=tan(2x)cos(2x)