What is expand (yln(y)-e^{-xy})dx ?

The solution to expand (yln(y)-e^{-xy})dx is yln(y)dx-e^{-yx}dx

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expand (yln(y)-e^{-xy})dx

expand

(y ln (y) - e^{- x y}) d x

y ln (y) d x - e^{- y x} d x

Solution steps

(y ln (y) - e^{- x y}) d x

= (y ln (y) - e^{- y x}) d x

Apply the distributive law:

a (b - c) = ab - a c

a = d x, b = y ln (y), c = e^{- x y}

= d x y ln (y) - d x e^{- x y}

= y ln (y) d x - e^{- y x} d x

\frac{1}{( x ) ( x - 1 ) ( x + 6 )}

d x (\frac{10}{z ^{2}} - \frac{4}{z ^{6}})

(6 x^{2}) (e^{- 2 x}) + (2 x^{3} - 1) (- 2 e^{- 2 x})

(\frac{2 x}{y ^{2}})^{5}

\frac{( 1 - cos ( z ) )}{( z ^{3} ( z - 3 ) )}

What is expand (yln(y)-e^{-xy})dx ?
The solution to expand (yln(y)-e^{-xy})dx is yln(y)dx-e^{-yx}dx