What is expand (5(2x-5)^2)/4 ?

The solution to expand (5(2x-5)^2)/4 is 5x^2-25x+125/4

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expand (5(2x-5)^2)/4

expand

\frac{5 ( 2 x - 5 ) ^{2}}{4}

5 x^{2} - 25 x + \frac{125}{4}

Solution steps

\frac{5 ( 2 x - 5 ) ^{2}}{4}

(2 x - 5)^{2} = 4 x^{2} - 20 x + 25

= \frac{5 ( 4 x ^{2} - 20 x + 25 )}{4}

Expand

5 (4 x^{2} - 20 x + 25) : 20 x^{2} - 100 x + 125

= \frac{20 x ^{2} - 100 x + 125}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{20 x ^{2} - 100 x + 125}{4} = \frac{20 x ^{2}}{4} - \frac{100 x}{4} + \frac{125}{4}

= \frac{20 x ^{2}}{4} - \frac{100 x}{4} + \frac{125}{4}

Divide the numbers:

\frac{20}{4} = 5

= 5 x^{2} - \frac{100 x}{4} + \frac{125}{4}

Divide the numbers:

\frac{100}{4} = 25

= 5 x^{2} - 25 x + \frac{125}{4}

\frac{( 5 x ^{2} + 60 x - 5 )}{( x + 1 ) ( x - 4 ) ( x + 5 )}

\frac{\partial}{\partial x} ((y) (3 x^{2} - 12 y))

\frac{12}{( x + 12 ) ^{2}}

\frac{d ^{2}}{d x ^{2}} ((y) (- 4 x + 40))

x y^{''} (x) + 2 y^{'} (x) - \frac{2 x y}{( 1 - x ) ^{2}}

What is expand (5(2x-5)^2)/4 ?
The solution to expand (5(2x-5)^2)/4 is 5x^2-25x+125/4