What is the answer to 7(t^2+5t-9)+t=t(7t-2)+13 ?

The answer to 7(t^2+5t-9)+t=t(7t-2)+13 is t=2

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7(t^2+5t-9)+t=t(7t-2)+13

7 (t^{2} + 5 t - 9) + t = t (7 t - 2) + 13

t = 2

Solution steps

7 (t^{2} + 5 t - 9) + t = t (7 t - 2) + 13

Expand

t (7 t - 2) : 7 t^{2} - 2 t

7 t^{2} + 36 t - 63 = 7 t^{2} - 2 t + 13

Expand

7 (t^{2} + 5 t - 9) + t : 7 t^{2} + 36 t - 63

7 t^{2} + 36 t - 63 = 7 t^{2} - 2 t + 13

Move

63

to the right side

7 t^{2} + 36 t = 7 t^{2} - 2 t + 76

Subtract

7 t^{2} - 2 t

from both sides

7 t^{2} + 36 t - (7 t^{2} - 2 t) = 7 t^{2} - 2 t + 76 - (7 t^{2} - 2 t)

Simplify

38 t = 76

Divide both sides by

38

t = 2

64 b^{2} - 81

\frac{8 - x}{x + 6} \geq 0

3 x^{2} (2 x^{2} + 3) = 0

(10 x + 3)^{2} = 3

\frac{( x - 5 )}{x + 2} \geq - 6

What is the answer to 7(t^2+5t-9)+t=t(7t-2)+13 ?
The answer to 7(t^2+5t-9)+t=t(7t-2)+13 is t=2
Solve for t: 7(t^2+5t-9)+t=t(7t-2)+13
The solution is t=2