What is factor n^3-5n^2-3n+15 ?

The solution to factor n^3-5n^2-3n+15 is (n-5)(n^2-3)

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factor n^3-5n^2-3n+15

factor

n^{3} - 5 n^{2} - 3 n + 15

(n - 5) (n^{2} - 3)

Solution steps

n^{3} - 5 n^{2} - 3 n + 15

= (n^{3} - 5 n^{2}) + (- 3 n + 15)

Factor out

n^{2}

from

n^{3} - 5 n^{2} : n^{2} (n - 5)

Factor out

- 3

from

- 3 n + 15 : - 3 (n - 5)

= n^{2} (n - 5) - 3 (n - 5)

Factor out common term

n - 5

= (n - 5) (n^{2} - 3)

\frac{3 y - 2}{7} = \frac{y + 6}{4}

(x - 2)^{2} - 9 \geq 0

x^{4} - x^{3} - 8 x^{2} + 12 x

\frac{3 ( 2 ^{2} c ^{4} d ^{5} ) ^{3}}{( 2 c d ^{2} ) ^{4}}

\frac{a ^{\frac{1}{3}}}{a ^{\frac{1}{4}}}

What is factor n^3-5n^2-3n+15 ?
The solution to factor n^3-5n^2-3n+15 is (n-5)(n^2-3)