What is 2(2.4016*10^{-11})(150) ?

The solution to 2(2.4016*10^{-11})(150) is 4503/625000000000

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simplify 2(2.4016*10^{-11})(150)

simplify

2 (2.4016 \cdot 1 0^{- 11}) (150)

\frac{4503}{625000000000}

Decimal Notation

7.2048 E - 9

Solution steps

2 (2.4016 \cdot 1 0^{- 11}) (150)

Apply rule:

(a) = a

(150) = 150

= 2 \cdot 2.4016 \cdot 1 0^{- 11} \cdot 150

Multiply the numbers:

2 \cdot 2.4016 \cdot 150 = 720.48

= 720.48 \cdot 1 0^{- 11}

= 1 0^{- 11} \cdot 720.48

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 11} = \frac{1}{1 0 ^{11}}

= \frac{1}{1 0 ^{11}} \cdot 720.48

\frac{1}{1 0 ^{11}} \cdot 720.48 = \frac{720.48}{1 0 ^{11}}

= \frac{720.48}{1 0 ^{11}}

\frac{720.48}{1 0 ^{11}} = \frac{72048}{100 \cdot 1 0 ^{11}}

= \frac{72048}{100 \cdot 1 0 ^{11}}

Factor the number:

72048 = 4 \cdot 18012

= \frac{4 \cdot 18012}{100 \cdot 1 0 ^{11}}

Factor the number:

100 = 4 \cdot 25

= \frac{4 \cdot 18012}{4 \cdot 25 \cdot 1 0 ^{11}}

Cancel the common factor:

4

= \frac{18012}{25 \cdot 1 0 ^{11}}

Factor

18012 : 2^{2} \cdot 4503

= \frac{2 ^{2} \cdot 4503}{25 \cdot 1 0 ^{11}}

Factor

1 0^{11} : 2^{11} \cdot 5^{11}

= \frac{2 ^{2} \cdot 4503}{25 \cdot 2 ^{11} \cdot 5 ^{11}}

\frac{2 ^{2}}{2 ^{11}} = \frac{1}{2 ^{9}}

= \frac{4503}{25 \cdot 2 ^{9} \cdot 5 ^{11}}

25 \cdot 2^{9} \cdot 5^{11} = 625000000000

= \frac{4503}{625000000000}

e^{- 3} (\frac{3 ^{0}}{0 !} + \frac{3 ^{1}}{1 !} + \frac{3 ^{2}}{2 !})

e^{- \frac{1}{2} (\frac{1}{2})^{2} \frac{1}{2}}

x^{2} y^{2} (y^{4} - 5 x^{2})

1.72 \cdot 1 0^{- 3}

3 e^{- e (3)} (3^{2} - 16) (3^{2} + 1) (3 - 1)^{4}

What is 2(2.4016*10^{-11})(150) ?
The solution to 2(2.4016*10^{-11})(150) is 4503/625000000000