What are the solutions to the equation y^2-8y+1=0 ?

The solutions to the equation y^2-8y+1=0 are y=4+sqrt(15),y=4-sqrt(15)

Find the zeros of y^2-8y+1=0

The zeros of y^2-8y+1=0 are y=4+sqrt(15),y=4-sqrt(15)

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y^{2} - 8 y + 1 = 0

y = 4 + 15, y = 4 - 15

Decimal Notation

y = 7.87298 \dots, y = 0.12701 \dots

Solution steps

y^{2} - 8 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 1 = 215

y_{1, 2} = \frac{- ( - 8 ) \pm 2 15}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 15}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 15}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 15}{2 \cdot 1} : 4 + 15

y = \frac{- ( - 8 ) - 2 15}{2 \cdot 1} : 4 - 15

The solutions to the quadratic equation are:

y = 4 + 15, y = 4 - 15

\frac{\frac{f ^{2} - q ^{2}}{f q}}{\frac{f - q}{q}}

n^{2} + 34 + 225

50 x^{2} - 18

x^{2} + 6 x = 9

- 7 x + 9 = 2 x - 99

What are the solutions to the equation y^2-8y+1=0 ?
The solutions to the equation y^2-8y+1=0 are y=4+sqrt(15),y=4-sqrt(15)
Find the zeros of y^2-8y+1=0
The zeros of y^2-8y+1=0 are y=4+sqrt(15),y=4-sqrt(15)