What is evaluate\sqrt[5]{253}^2 ?

The solution to evaluate\sqrt[5]{253}^2 is 253^{2/5}e^2lva^2ut

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simplify evaluate\sqrt[5]{253}^2

simplify

25 3^{\frac{2}{5}} e^{2} l v a^{2} u t

Solution steps

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

Add the numbers:

1 + 1 = 2

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

aa = a^{1 + 1}

Add the numbers:

1 + 1 = 2

= 25 3^{\frac{2}{5}} e^{2} l v a^{2} u t

8 h m^{2445} d a m^{24} m^{2}

100 \cdot 1 0^{- 6} \cdot 20 (1.22856 - 0.6)^{2}

\frac{1}{2} (1.673 \cdot 1 0^{- 27}) ((604)^{2})

(f g \circ f) (\frac{3 x - 2}{5})^{3}

\frac{1}{2 \cdot π} \cdot e^{- 0.5 \cdot 0}

What is evaluate\sqrt[5]{253}^2 ?
The solution to evaluate\sqrt[5]{253}^2 is 253^{2/5}e^2lva^2ut