What is ((m^7*m)/(z^2*m^3))^2 ?

The solution to ((m^7*m)/(z^2*m^3))^2 is (m^{10})/(z^4)

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simplify ((m^7m)/(z^2m^3))^2

simplify

(\frac{m ^{7} \cdot m}{z ^{2} \cdot m ^{3}})^{2}

\frac{m ^{10}}{z ^{4}}

Solution steps

(\frac{m ^{7} m}{z ^{2} m ^{3}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( m ^{7} m ) ^{2}}{( z ^{2} m ^{3} ) ^{2}}

Simplify

(m^{7} m)^{2} : m^{16}

= \frac{m ^{16}}{( z ^{2} m ^{3} ) ^{2}}

Simplify

(z^{2} m^{3})^{2} : z^{4} m^{6}

= \frac{m ^{16}}{z ^{4} m ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{m ^{16}}{m ^{6}} = m^{16 - 6}

= \frac{m ^{16 - 6}}{z ^{4}}

Subtract the numbers:

16 - 6 = 10

= \frac{m ^{10}}{z ^{4}}

(2 x + 3) (x + 4) = 1

\frac{x - 1}{x + 1} \leq \frac{x + 3}{x - 5}

x^{2} - 5 x = 14

(\frac{3 x ^{2} y ^{5} z ^{- 2}}{5 x z ^{5}})^{- 3}

5 x^{2} + 6 x = - 5

What is ((m^7*m)/(z^2*m^3))^2 ?
The solution to ((m^7*m)/(z^2*m^3))^2 is (m^{10})/(z^4)