What is ((3x^2y^5z^{-2})/(5xz^5))^{-3} ?

The solution to ((3x^2y^5z^{-2})/(5xz^5))^{-3} is (125z^{21})/(27x^3y^{15)}

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simplify ((3x^2y^5z^{-2})/(5xz^5))^{-3}

simplify

(\frac{3 x ^{2} y ^{5} z ^{- 2}}{5 x z ^{5}})^{- 3}

\frac{125 z ^{21}}{27 x ^{3} y ^{15}}

Solution steps

(\frac{3 x ^{2} y ^{5} z ^{- 2}}{5 x z ^{5}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{3 x ^{2} y ^{5} z ^{- 2}}{5 x z ^{5}})^{- 3} = \frac{1}{( \frac{3 x ^{2} y ^{5} z ^{- 2}}{5 x z ^{5}} ) ^{3}}

= \frac{1}{( \frac{3 x ^{2} y ^{5} z ^{- 2}}{5 x z ^{5}} ) ^{3}}

Simplify

(\frac{3 x ^{2} y ^{5} z ^{- 2}}{5 x z ^{5}})^{3} : \frac{27 x ^{3} y ^{15}}{125 z ^{21}}

= \frac{1}{\frac{27 x ^{3} y ^{15}}{125 z ^{21}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{125 z ^{21}}{27 x ^{3} y ^{15}}

5 x^{2} + 6 x = - 5

y, 2 x - y + 5^{x - 1} = 7 \cdot 5

16 - 4

4 x + 2 = \frac{1}{2} x + 17

7 3^{2}

What is ((3x^2y^5z^{-2})/(5xz^5))^{-3} ?
The solution to ((3x^2y^5z^{-2})/(5xz^5))^{-3} is (125z^{21})/(27x^3y^{15)}