What is expand-2.55log_{10}(B/(Bo)) ?

The solution to expand-2.55log_{10}(B/(Bo)) is -2.55(log_{10}(B)-log_{10}(Bo))

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expand-2.55log_{10}(B/(Bo))

expand

- 2.55 lo g_{10} (\frac{B}{B o})

- 2.55 (lo g_{10} (B) - lo g_{10} (B o))

Solution steps

- 2.55 lo g_{10} (\frac{B}{B o})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{B}{B o}) = lo g_{10} (B) - lo g_{10} (B o)

= - 2.55 (lo g_{10} (B) - lo g_{10} (B o))

= - 2.55 (lo g_{10} (B) - lo g_{10} (B o))

\frac{( 0.35 ) ^{2} \cdot 13.86}{100 \cdot 61} \cdot ln (\frac{113}{100})

8 lo g_{b} (x) + 2 lo g_{b} (z)

- \frac{2 ln ( 10 x + 5 y - 2 )}{25} + \frac{2 x + y}{5}

ln (6) + ln (3)

ln (4) - ln (\frac{1}{4})

What is expand-2.55log_{10}(B/(Bo)) ?
The solution to expand-2.55log_{10}(B/(Bo)) is -2.55(log_{10}(B)-log_{10}(Bo))